Model 8 Population Based Practice Questions Answers Test With Solutions & More Shortcuts
PERCENTAGE PRACTICE TEST [11 - EXERCISES]
Model 1 Simple Percentage Questions
Model 2 Net Increase Or Decrease In %
Model 3 Reducing & Exceeding Prices
Model 4 X & Y Comparison
Model 5 Income & Expenditure
Model 6 Consumption & Remaining
Model 7 Marks Scored In Examinations
Model 8 Population Based
Model 9 Voters & Election
Model 10 Percentage With Allegations & Mixture
Model 11 Percentage With Ratios
Question : 26 [SSC CISF ASI 2010]
The value of an equipment depreciates by 20% each year. How much less will the value of the equipment be after 3 years ?
a) 51.2%
b) 48.8%
c) 54%
d) 60%
Answer »Answer: (b)
If the present worth of the equipment be Rs.100, then
its price after 3 years = 100 × $(80/100)^3$ = Rs.51.2
Depriciation = 48.8%
Using Rule 18,
If the population/cost of a town/article is P and it decreases/reduces at the rate of r% annually, then,
- After ‘t' years population/cost = $P(1 - r/100)^t$
- Before ‘t' years population/cost = $P/{(1 - r/100)^t}$
Let the price of equipment be Rs.100
Its price after 3 years. = $100(1 - 20/100)^3$
= $100 × (80/100)^3$ = Rs.51.2
Depriciation = 48.8%
Question : 27
If the population of a town is 64000 and its annual increase is 10%, then its correct population at the end of 3 years will be :
a) 85184
b) 80000
c) 85000
d) 85100
Answer »Answer: (a)
Using Rule 17,
Population of town = $P(1 + R/100)^T$
= $64000(1 + 10/100)^3$
= $64000 × 11/10 × 11/10 × 11/10$ = 85184
Question : 28
In a town, the population was 8000. In one year, male population increased by 10% and female population increased by 8% but the total population increased by 9%. The number of males in the town was :
a) 4500
b) 4000
c) 5000
d) 6000
Answer »Answer: (b)
By Alligation Rule
Men : Women = 1 : 1
Number of men = $1/2 × 8000 = 4000$
Question : 29 [SSC CISF Constable 2011]
If population of women in a village is 90% of population of men, what is the population of men as a percentage of population of women ?
a) 105%
b) 100%
c) 108%
d) 111%
Answer »Answer: (d)
If the number of men be 100,then
Number of women = 90
Required per cent = $100/90 × 100 ≈ 111%$
Question : 30 [SSC CGL Tier-I 2015]
The population of a town increases by 5% every year. If the present population is 9261, the population 3 years ago was
a) 5700
b) 8000
c) 6000
d) 7500
Answer »Answer: (b)
Using Rule 17,
P = $P_0(1 + R/100)^T$
9261 = $P_0(1 + 5/100)^3$
9261 = $P_0(1 + 1/20)^3$
9261 = $P_0(21/20)^3$
$P_0 = {9261 × 20 × 20 × 20}/{21 × 21 × 21}$ = 8000
IMPORTANT QUANTITATIVE APTITUDE EXERCISES
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Model 8 Population Based Shortcuts »
Click to Read...Model 8 Population Based Online Quiz
Click to Start..PERCENTAGE SHORTCUTS AND TECHNIQUES WITH EXAMPLES
-
Model 1 Simple Percentage Questions
Defination & Shortcuts … -
Model 2 Net Increase Or Decrease In %
Defination & Shortcuts … -
Model 3 Reducing & Exceeding Prices
Defination & Shortcuts … -
Model 4 X & Y Comparison
Defination & Shortcuts … -
Model 5 Income & Expenditure
Defination & Shortcuts … -
Model 6 Consumption & Remaining
Defination & Shortcuts … -
Model 7 Marks Scored In Examinations
Defination & Shortcuts … -
Model 8 Population Based
Defination & Shortcuts … -
Model 9 Voters & Election
Defination & Shortcuts … -
Model 10 Percentage With Allegations & Mixture
Defination & Shortcuts … -
Model 11 Percentage With Ratios
Defination & Shortcuts …
QUANTITATIVE APTITUDE CATEGORIES
-
» Number System
-
» Average
-
» LCM & HCF
-
» Percentage
-
» Profit & Loss
-
» Time & Work
-
» Pipes & Cisterns
-
» Time & Distance
-
» Trains
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» Compound Interest
-
» Simplification
-
» Discount
-
» Power
-
» Permutations & Combination
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» Ratio & Proportion
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» Advance Math
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» Algebraic Expressions
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» Trigonometric Ratios & Identities
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» Simple Interest
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» Alligation & Mixtures
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» Boats & Streams
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» Set Theory
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» Linear Equations
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» Quadratic Equations
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» Mensuration
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» Squareroots & Cuberoots
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» Data Sufficiency
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» Logarithm
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» Probability
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» Statistics
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